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TRICKY first VERSION with 660
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by
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trischi83
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ARNO                              2019-06-24 20:36
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FIRST VERSION?   
I SEE A CHANGE: ONE LIGHT BOULDER CAN NOW BE PUSHED BELOW THE SLIME. AND A HEAVY BOULDER HAS BEEN REPLACED BY SLIME...

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NESDORI                           2019-06-25 17:55
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THIS CAVE NOW MAKES MUCH MORE SENSE THAN THE VERSION "WHICH WAS RELEASED FIRST BUT APPARENTLY WAS NOT FIRST". IT'S A BIT BIZARRE TO ADD A HEAVY BOULDER WHICH BOTH RESERVES ONE SPOT FROM AMOEBA AND LIMITS OPTIONS AND STILL CLAIM THAT 660 IS POSSIBLE. THIS CAVE IS CLOSE BEING SOLVABLE. I THINK I CAN GET 659 DIAMONDS WITH THIS BUT STILL ONE DIAMOND IS MISSING. ONE EXTRA DIAMOND CAN BE OBTAINED FROM AMOEBA (THE HEAVY BOULDER SPOT) AND I THINK THIS CAVE CAN NOW BE SOLVED USING JUST 3 GATES SO THERE'S ANOTHER EXTRA DIAMOND.  
  
THIS IS THE "3-GATES IDEA": PUSH THE LIGHT BOULDER BELOW SLIME TO THE RIGHTMOST SPOT UNDER THE LAST COLUMN. THERE'S ONLY ON SLOT WHERE A BOULDER CAN BE PUSHED AND THE STOPPED COLUMN WILL ALWAYS BE: BBDDDDBB. BECAUSE THE UNDERMOST OBJECT IS A BOULDER NOW HE HAVE TO MOVE ALL DIAMONDS FROM THE SECOND RIGHTMOST COLUMN TO OTHER COLUMNS BY STOPPING A FLOW OF COLUMNS ONE AT A TIME. THIS PHASE IS CHALLENGING BECAUSE COLUMNS ARE SO FULL OF OBJECTS BUT IN THEORY IT SHOULD BE POSSIBLE. I'M NOT SURE IF IT ACTUALLY IS. AFTER THE SECOND RIGHTMOST COLUMN CONTAINS ONLY BOULDERS THE ROOM CAN BE ENTERED AND THEN TWO BOULDERS SHOULD BE DISPOSED FROM THE SECOND COLUMN BY BLOCKING MAGIC WALL SO THAT THE 2 UPPER BOULDERS FROM 1ST COLUMN WILL FALL TO 2ND AND 4 DIAMONDS FROM THE FIRST ONE CAN BE PICKED AND AFTER THAT THE ENTIRE 2ND COLUMN CAN BE DISPOSED AND IT'S TRIVIAL TO PICK UP THE REMAINING DIAMONDS AND CLEAR THE ROOM. THE UNDERMOST BOULDER OF 1ST COLUMN OF COURSE REMAINS LEFT BECAUSE THE LIGHT BOULDER IS STILL BLOCKING IT. NOW THE ROOM CAN BE LEFT AND THE LIGHT BOULDER PUSHED TO LEFT AGAIN AND USE IT TO FREE AMOEBA. THEN WE HAVE TO DISPOSE THE REMAINING BOULDER WHICH IS NOW FREE-FALLING. THERE'S TWO METHODS TO DO THAT WITHOUT ENTERING THE ROOM AGAIN. WHEN AMOEBA IS FREE, GO BACK TO BELOW SLIME AND STOP THE BOULDER FROM FALLING. THEN AMOEBA ENTERS THE ROOM AND WHEN IT'S CLOSE TO UPPER RIGHT CORNER, RELEASE THE BOULDER AND LET IT FALL ONE MORE ROUND. HOPEFULLY THE AMOEBA WILL REACH UPPER RIGHT CORNER DURING THE LAST FALL AND THEN WILL DISPOSE THE BOULDER. ALSO OTHER PARTS OF AMOEBA SHOULDN'T BLOCK THE FALL SO LUCK IS NEEDED. IT'S HARD TO ESTIMATE HOW OFTEN THIS WOULD SUCCEED. ANOTHER OPTION IS JUST THEORETICAL: GO TO A RIGHT SIDE GATE AND WHEN AMOEBA REACHES ROCKFORD, USE "GATE-TRICK" TO ENTER WITH AMOEBA AND THEN BLOCK THE REMAINING STONE WITH ROCKFORD. FOR THIS TO SUCCEED, YOU HAVE TO BE EXTREMELY LUCKY BECAUSE AMOEBA SHOULD REACH ROCKFORD FROM THE RIGHT SIDE BEFORE AMOEBA FILLS THE ROOM AND EITHER SUFFOCATES BOULDER OR BLOCKS ROCKFORD. TO REACH ROCKFORD FROM RIGHT AMOEBA HAS TO CRAWL ALONG BOTTOM CORRIDOR WHILE UPPER PART OF AMOEBA AND SPREAD FREELY IN THE ROOM. SO IT PROBABLY TAKES ENTIRE LIFETIME OF TRIES THIS TO SUCCEED AND METHOD #2 IS PURELY THEORETICAL :)  
  
SO, 659 PROBABLY IS POSSIBLE BUT BUT BECAUSE THE REST OF CAVE IS SAME AS THE CAVE WHICH WAS PUBLISHED EARLIER I STILL DON'T SEE A WAY TO GET 660.

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ARNO                              2019-06-25 21:49
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THANKS nesdori!  
  
I HOPE trischi WILL ONCE SHOW US THE WAY HE ORIGINALLY HAD IN MIND! :-)