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2023-09-09 16:01 helena  
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Wow! That's an amazing accomplishment! And a puzzling rhyme, looking forward to the demo's ?

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2023-09-09 16:02 helena  
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* ;-)

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2023-09-09 17:55 dustin  
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thank you  Helena ! it's a lot of fun, and it's thanks to  Arno  that i joined this site :d  
  
as for the puzzle, you can also see it as a purely mathematical puzzle:  
| you have 13 objects, numbered from 1-13.  
| seven objects can be "trusted", the other six are not trustworthy.  
| the puzzle is there to find out the trustworthy ones.  
;)

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2023-09-09 18:06 altermaven  
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can't solve the puzzle if I can't find a way "in" ;)

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2023-09-09 20:00 DarkStoorM  
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2000 wooo :D  that was quite a ride!

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2023-09-09 21:07 Arno  
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congrat with your cave no. 2000  dustin ! :-D  
  
nice cave and puzzle!   
  
as two mathematicians,  Helena  and i solved the mathematical puzzle together. and she supported me during the run, so we had much fun...! ;-D

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2023-09-10 09:29 dustin  
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 altermaven : true, the "way in" is already not so easy, Κ has to master a few quests :d  
  
 darkstoorm : thanks :d   
  
 Arno : thanks :d now i have pictures in my head where you lead Κ through the quests and  Helena  is watching you and cheering you on 'ar-no! rock-ford! ar-no! rock-ford!" and then celebrating when you saw that your common puzzle solution was indeed correct :d :d

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2023-09-10 18:44 Arno  
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:-D

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2023-09-15 11:04 dustin  
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my run free! :D  
  
s p o i l e r: here's the solution of the riddle!  
  
seven rocks - seven rhymes  
don't trust all 13 slimes!  
in the final room, there are seven rocks and 13 slimes. if Κ wants to get all ΑΑΑ without getting stuck, he needs to push each Β onto a "trustworthy" (impermeable) piece of slime.   
  
trust the lowest two primes  
the first two prime numbers are 2 and 3, so these slimes are impermeable.  
  
and their plus and their times  
2+3=5, 2*3=6, so the 5th and 6th slimes are also impermeable.  
  
and their power (both kinds).  
2 to the power of 3 =8, 3 to the power of 2 =9, so the 8th and 9th slimes are impermeable.  
  
trust the number on dimes.  
a dime is a 10-cent-coin, so the 10th slime is impermeable.  
  
but the others do crimes!  
none of the other slimes is impermeable.  
  
that's why the ΒΒΒ have to be pushed onto the 2nd, 3rd, 5th, 6th, 8th, 9th and 10th slimes! :d  
  
trivia:  
  
| the cave kind of tricks the "show impermeable slimes" feature in the ckit. if you try to use this, then it will show all the 13 slimes as permeable! this is because the "impermeable" slimes are actually permeable in the very first frame, when the rng is still pre-periodic.  
  
| the cave has 73*13 = 949 slimes in total. this is equal to the period length of the rng, which means that each Ι only gets one and the same rng value each frame. so each slime is either impermeable or behaves like permeability zero.   
  
| also it was necessary to put 949 slimes into the caves in order to trick the "show impermeable slimes" feature!  
  
| the funny thing about the riddle is that i had no choice about the solution. it was defined by the rng which slimes are permeable, so i had to work with these and make a riddle around the given solutions. it was already cool that the mathematics (lines 3-5 of the riddle) worked out that well, but i still needed something for the 10. i googled rhymes and i was delighted when i found that a "dime" is a 10 cent coin - exactly what i needed! :d  
  
| i designed the whole cave when the "impermeability" topic was hot here at this site, which must be more than a year ago. first i made only room 6, then i thought that it would be too easy to just trial-and-error this. that's how i got the idea to make more rooms, so it would already be a difficult quest to get access to the puzzle, so if Κ fails to solve it on 1st try, then he would have to do the whole cave again! it was only a few days ago that i got the idea to make my 2000th cave out of this one :d

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2023-09-15 11:29 altermaven  
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looking at how room four is done the only thing i could say is "perkele"...