# .font: font.text_2
2024-02-03 21:05 dustin  
# .font: font.text_1
my solution free! :d  
  
explanations:  
| it's necessary to push the Β 1 left, so the ΑΑΑ from the first Η will reach the left Η cage.  
| to reach the right Η as well, the top-left Α from the first Η must fall right. normally it would fall left, however. that's why Κ needs to block the Α's way.  
  
how this works frame by frame:  
  
___Κ_____  
___123___  
___456___  
___789___  
ΓΓΓΓΓΓΓΓΓ  
  
(_ represents empty space, numbers represent the ΑΑΑ which were just created from the first Η explosion. they're now going to fall.)  
1 and 4 fall left, 3 and 6 fall right. next frame:  
  
___Κ_____  
__1_2_3__  
__4_5_6__  
___789___  
ΓΓΓΓΓΓΓΓΓ  
  
now comes the decisive moment. 2 can fall either left or right, and it will always choose to fall left if given the choice. but that Α is needed for the right Η cage, so Κ now moves down (he is scanned first) and blocks the Α's way:  
  
_________  
__1Κ_23__  
____5____  
__47896__  
ΓΓΓΓΓΓΓΓΓ  
  
the rest is straightforward. 1 will crush the left Η, while 2,3,5,8,9 and 6 will form the slope to reach the right Η as well!  
  
note that in my run, i already pre-created the slope, which is not necessary. :d